a student goes from his house to his friends house with speed v1. and return back to his house with speed v2. then average speed and net displacement of a student is.!?
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Answered by
2
Answer:
average speed = (v1+v2)/2 Net displacement is 0
Explanation:
average speed formula is (speed1+speed2)/2 so average speed is (v1+v2)/2. And since he comes back to the starting point (his house) net displacement will be 0. Hope it is clear!
Answered by
0
Answer:
v1 + v2/ 2 is answer
Explanation:
hope it is helpful to you
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