Math, asked by Gurnehmat, 8 months ago

A student got thrice as many sums rights as he got wrong. If
he attempted 96 sums in all, how many did he solve correctly
Explain in an easy way??

Answers

Answered by mishikag2007
2

Answer:

Answer 72

Step-by-step explanation:

Let the number of wrong sums be = x

Then he got thrice as many sums right as he got wrong => Number of sums right = 3x

Total number of sums he solved = Right Sums + Wrong Sums => Total number of sums he solved =3x + x =4x4x =96 => x = 24 solved correctly = 3x =3 *24 = 72

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