A student got thrice as many sums rights as he got wrong. If
he attempted 96 sums in all, how many did he solve correctly
Explain in an easy way??
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Answer:
Answer 72
Step-by-step explanation:
Let the number of wrong sums be = x
Then he got thrice as many sums right as he got wrong => Number of sums right = 3x
Total number of sums he solved = Right Sums + Wrong Sums => Total number of sums he solved =3x + x =4x4x =96 => x = 24 solved correctly = 3x =3 *24 = 72
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