A student has connected a battery of 12V in a series combination of resistors 3Ω, 4Ω, 5Ω and 12Ω. Current flowing through the 12Ω resistor is ____________________. (1 Point)
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62
Given :
▪ Four identical resistors of resistances 3Ω, 4Ω, 5Ω and 12Ω are connected in series with a battery of volatage 12V.
To Find :
▪ Current through 12Ω resistor.
Concept :
☞ As per ohm's law, current passing through a conductor is directly proportional to the applied pd.
☞ We know that, Current flow in all resistors remains same in series connection.
Calculation :
✴ Eq. resistance :
→ Req = R1 + R2 + R3 + R4
→ Req = 3 + 4 + 5 + 12
→ Req = 24Ω
✴ Current flow :
→ V = IReq
→ 12 = I×24
→ I = 12/24
→ I = 0.5A
Current flowing through 12Ω resistor = 0.5A
Answered by
43
- when resistors are connected in series and ask that “Current flowing through any one of those resistor”, then
- First calculate ‘The Equivalent Resistance’ .
- Then Using Ohm's Law to find Current Flowing through that resistor .
- We also know that, current flowing through all resistor is remain same in series connection .
(☞ A student has connected a battery of 12V in series combination of resistors 3 Ohm , 4 Ohm , 5 Ohm and 12 Ohm .
- Voltage (V) = 12 V
(☞ Current flowing through 12 Ohm resistor = ?
(☞ Equivalent Resistance;
=
(☞ Voltage (V) = 12 V
FORMULA:-
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