Physics, asked by ravigiri952, 11 months ago

A student has connected a battery of 12V in a series combination of resistors 3Ω, 4Ω, 5Ω and 12Ω. Current flowing through the 12Ω resistor is ____________________. (1 Point)

Answers

Answered by Anonymous
62

Given :

▪ Four identical resistors of resistances 3Ω, 4Ω, 5Ω and 12Ω are connected in series with a battery of volatage 12V.

To Find :

▪ Current through 12Ω resistor.

Concept :

☞ As per ohm's law, current passing through a conductor is directly proportional to the applied pd.

☞ We know that, Current flow in all resistors remains same in series connection.

Calculation :

Eq. resistance :

→ Req = R1 + R2 + R3 + R4

→ Req = 3 + 4 + 5 + 12

Req = 24Ω

Current flow :

→ V = IReq

→ 12 = I×24

→ I = 12/24

I = 0.5A

Current flowing through 12Ω resistor = 0.5A

Answered by DARLO20
43

\bigstar \sf{\green{\underline{\underline{\orange{CONCEPTS:-}}}}}

  • when resistors are connected in series and ask that Current flowing through any one of those resistor”, then
  1. First calculate The Equivalent Resistance .
  2. Then Using Ohm's Law to find Current Flowing through that resistor .
  • We also know that, current flowing through all resistor is remain same in series connection .

\bigstar \sf{\green{\underline{\underline{\orange{Given:-}}}}}

(☞ A student has connected a battery of 12V in series combination of resistors 3 Ohm , 4 Ohm , 5 Ohm and 12 Ohm .

  • Voltage (V) = 12 V
  • {R_1\:=\:3\:Ohm}
  • {R_2\:=\:4\:Ohm}
  • {R_3\:=\:5\:Ohm}
  • {R_4\:=\:12\:Ohm}

\bigstar \sf{\green{\underline{\underline{\orange{To\:Find:-}}}}}

(☞ Current flowing through 12 Ohm resistor = ?

\bigstar \sf{\green{\underline{\underline{\orange{SOLUTION:-}}}}}

(☞ Equivalent Resistance;

{R_{eq}} = {R_1\:+\:R_2\:+\:R_3\:+\:R_4}

\tt{\implies\:R_{eq}\:=\:3\:+\:4\:+\:5\:+\:12}

\tt{\implies\:R_{eq}\:=\:24\:Ohm}

(☞ Voltage (V) = 12 V

\bigstar FORMULA:-

{Current\:(I)\:\:={\dfrac{V}{R_{eq}}}}

\tt{\implies\:I\:=\:{\dfrac{12\:V}{24\:Ohm}}}

\tt{\implies\:I\:=\:0.5\:Ampere}

\bigstar\:\underline{\boxed{\bf{\red{Required\:Answer\::0.5\:A}}}}

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