Question

A student has several coins, consisting of nickels and dimes, that amount to $42.15. If the number of dimes exceeds 3 times the number of nickels by 4, find the number of each kind of coin.

Answer 1

Answer:

Here is your answer

Step-by-step explanation:

10D + 5N = 215

 

D = 3N+4

 

10(3n+4) + 5n = 215

 

30n + 40 + 5n = 215

 

35n + 40 = 215

 

35n = 175

 

n = 5

 

5 nickles

19 dimes

 

$1.90 + 0.25 = 2.15

Answer 2

Answer:

here it is:-

Step-by-step explanation:

10D + 5N = 215

D = 3N+4

10(3n+4) + 5n = 215

30n + 40 + 5n = 215

35n + 40 = 215

35n = 175

n = 5

5 nickles

19 dimes

$1.90 + 0.25 = 2.15