A student has to put a resistor in place of R2 as shown in the circuit. The current that
he needs in the circuit is exactly 2 A. Show by calculation, the value of R2, which he
should use.
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The overall current needed = 9A. The voltage is 12V Hence by Ohm’s Law V=IR, The resistance for the entire circuit = \(\frac{12}{9}\) = \(\frac{4}{3}\Omega\) = R R1 and R2 are in parallel. Hence, R=\(\frac{(R_1R_2)}{(R_1+R_2)}\)= \(\frac{4R_2}{(4+R_2)}\)= \(\frac{4}{3}\) R2 = 2\(\Omega\)Read more on Sarthaks.com - https://www.sarthaks.com/972176/student-has-two-resistors-and-she-has-to-put-one-of-them-in-place-of-r2-as-shown-in-the-circuit
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