Question

A student has to secure 33 \% of the maximum marks to pass. He secures 295 marks and fails by 200 marks. Find the maximum marks. ( A ) 1550 ( B ) 1400 ( C ) 1500 ( D ) 1600

Answer 1

Answer:

C. 1500

Step-by-step explanation:

let the maximum marks be x

so, passing marks =33/100*x

if he fails for 200 marks, and he get 295 marks

again passing marks = 295+200=495

=33/100*x=495

=x=495*100/33

=1500.

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Answer 2

( C ) 1500

The maximum marks is 1500.

Explanation:

Let x be the maximum marks .

Given : A student has to secure 33 % of the maximum marks to pass.

i.e.  Passing marks = 33 % of x = 0.33 x                           (1 )

[we divide % by 100 to convert it into decimal]

Since , He secures 295 marks and fails by 200 marks.

i.e. Passing marks- 200 = 295

i.e. Passing marks= 295+200=495                           (2 )

From (1) and (2) , we have

$0.33x=495\\\\ x=\dfrac{495}{0.33}=\dfrac{49500}{33}=1500$

Hence, the maximum marks is 1500.

Thus , the correct answer is  ( C ) 1500 .

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In an examination a student secured 26%and failed it by 28 marks if the pass percentage is 33%find the maximum marks