Math, asked by heythere4197, 1 year ago

A student has to secure 40% of marks to pass he got 178 and fails by 22 marks the maximum marks are?

Answers

Answered by Akashchamp2144
4
He got 178 and failed by 22. Also, pass percentage is 40. So 40%=178+22=200.
Then, Let max. marks be A.
ATQ
200/A X 100 = 40
> 20000/A =40
20000=40A
A= 20000/40
A=500.

Hence, max. marks are 500.
Answered by mayur451998
1
if he failed by 22 marks then he will be required 178+22= 200 marks in total for passing.
if 200 is 40% then
X × 40% = 200
X = 200 ÷ 40%
X = 500 marks
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