a student has to secure 40% to pass. He sets 217 marks and fails by 22 marks. The maximum marks is?
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Answered by
1
Answer:
Step-by-step explanation:total passing marks=217+22=239
40% marks=239
Therefore total marks(100%)=239*100/40
=597.5 marks
Answered by
0
Answer:
Minimum marks to pass the exam = 178 + 22 = 200
200 marks is 40% of Maximum marks
200 = 40% × Maximum marks
Maximum marks = 200 × 100 / 40 = 500
∴ Maximum marks of exam is 500
Step-by-step explanation:
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