a student has two resisters 2Ω and 3Ω,she has to put one of them in a circuit, which total has 9A. which one should she use?
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Answer:
your answers is 2Ω
here is the solution
let R² be 2Ω
so 1/Req = ¼ + ½
1/Req = ¾
Req = ⁴/3
now by ohms law R = V/I
I = V/R
I = 12 / ⁴/3
I = 9A
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