Question

A student has two resistors- 2 Ω and 3 Ω. She has to put one of them in place

of R2 as shown in the circuit. The current that she needs in the entire circuit is

exactly 9A. Show by calculation which of the two resistors she should choose.​

Answer 1

Students has to put  2 ohm  Resistor in place of R2

Explanation:

Battery Source = 12 V

=> V = 12 V

Total Current = 9 A

Total Resistance = R  

V = IR

=> 12  = 9R

=> 4 = 3R

=> R = 4/3  

R1  & R2 are in Parallel

Hence

1/R   =  1/R1  + 1/R2

=> 1/(4/3)  = 1/4  + 1/R2

=> 3/4  = 1/4 + 1/R2

=> 2/4  = 1/R2

=> 1/2 = 1/R2

=> R2  = 2

Students has to put  2 ohm  Resistor in place of R2

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Answer 2

$\huge\underbrace\mathfrak \red{ANSWER }$

Students has to put  2 ohm  Resistor in place of R2

Explanation:

Battery Source = 12 V

=> V = 12 V

Total Current = 9 A

Total Resistance = R  

V = IR

=> 12  = 9R

=> 4 = 3R

=> R = 4/3  

R1  & R2 are in Parallel

Hence

1/R   =  1/R1  + 1/R2

=> 1/(4/3)  = 1/4  + 1/R2

=> 3/4  = 1/4 + 1/R2

=> 2/4  = 1/R2

=> 1/2 = 1/R2

=> R2  = 2

Students has to put  2 ohm  Resistor in place of R2

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