A student has two solutions of a substance
solution 1:25M, 400ml and solution2 : 30M,300ml
So what is the the molarity
of the final solutions if these two Solutions are mixed
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Answer:
M=M1V1+M2V2/V1+V2.
M=25×400+30×300/400+300. , M= 10000+9000/700 , M=19000/700 ,M= 27.14M
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