Question

A student is able to throw a ball vertically to maximum height of 40m the maximum distance to which the student can throw the ball in horizontal direction-

Answer 1

$maximum \: height = \frac{ {u}^{2} }{2g} \\ \\ maximum \: range = \frac{ {u}^{2} }{g} \\ \\ given \: that - \\ \\ \frac{ {u}^{2} }{2g} = 40 \\ \\ \frac{ {u}^{2} }{g} = 80$
hence max. range is 80 m

Answer 2

Answer:

hope it helps u sir ❤❤❤❤❤❤❤❤