Question

a student is asked to mix 20 gram of common salt and 320 gram of water in beaker name the solution he will observe in the beaker after staring the mixture also calculate the number of moles of common salt present in the solution ​

Answer 1

Brine solution.

No. Of mole common salt present in this solution is 2

Answer 2

This solution is called salt water solution. And no. of moles =0.34 mol

Explanation:No. of moles =Given Mass/ Molar Mass

=20g/58.5g (NaCl)

=0.34 mol.