A student is given a 3.589g mixture of iron filings, calcium chloride and sand. She separates the mixture and recovers 0.897g of iron, 0.923g of sand and 1.686g of calcium chloride. calculate the percentage of each of the three components she recovered from the original mixture and the percent of material she lost during the separation process.
Answers
Given:
Mass of total Mixture= 3.589g
Mass of iron= 0.897g
Mass of sand= 0.923g
Mass of calcium chloride=1.686g
To find:
Percentage of material she lost during separation =?
Solution:
Percentage of iron= (Mass of iron/Mass of total Mixture)*100
= (0.897/3.589)*100
= 24.99%
Percentage of sand= (Mass of sand/Mass of total Mixture)*100
= (0.923/3.589)*100
= 25.71%
Percentage of calcium chloride
= (Mass of calcium chloride/Mass of total Mixture)*100
= (1.686/3.589)*100
= 46.97%
Percentage of material she lost during seperation= 100-(24.99+25.71+46.97)
=100-97.67
=2.33
Hence, the Percentage of material she lost during separation is 2.33%