Question

A student is given a 6.216g mixture of iron filings, calcium chloride and sand. He separetes the mixture and recovers 2.524g of iron, 1.932 of sand and 1.523g of calcium chloride. Calculate the percentage of each component he recovered from the original mixture and the percent of material he lost during the seperation process.

Answer 1

Explanation:

Mass of the mixture =  6.216 g

Mass of iron recover = 2.524 g

Percentage of iron recovered from the mixture:

$\frac{2.524 g}{6.216 g}\times 100=40.60\%$

Mass of sand recover  = 1.932 g

Percentage of sand recovered from the mixture:

$\frac{1.932 g}{6.216 g}\times 100=31.08\%$

Mass of calcium chloride recover  = 1.523 g

Percentage of calcium chloride recovered from the mixture:

$\frac{1.523 g}{6.216 g}\times 100=24.50\%$

Mass of mixture lost during separation :

6.216 g - 2.524 g - 1.932 g- 1.523 g = 0.237 g

Percent of material he lost during the separation process:

$\frac{0.237 g}{6.216 g}\times 100=3.81\%$