A student is measuring the amount of water in a graduated cylinder and reports a value of 24 mL. The teacher reports the value as 24.2 mL. What is the student's percent error?
a)+0.83%
b)-0.83%
c)+0.2%
d)-0.2%
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Answers
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basic formulas
1.Absolute error = |Vtrue - Vobserved|
2.Relative error= {Vtrue - Vobserved}/Vtrue
3.Percentage error = {Vtrue - Vobserved}/Vtrue × 100
Percent Error =
{Vobserved - Vtrue
}/Vtrue
=
{24 - 24.2
}/24.2
=
{-0.2
}/24.2
= -0.82644628099173%
= 0.82644628099173% error [option A]
i srly hope this helps becuase now my fingers are hurting...
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