Question

A student is standing on top of the school building (which they shouldn’t be doing) and has a height of 78.4m. They kick a rock off the edge of the building with a velocity of 6 m/s
How long does it take the rock to fall?

How far away from the base of the building does the rock land?

Answer 1

Answer:

s = ut + 1/2at²

78.4 = 0 + 1/2 (9.8)t²

78.4 = 4.9t²

t² = 78.4÷4.9

t² = 16

t = 4

Explanation:

acceleration while coming down is always positive and negative when going up

when going upward final velocity (v) = 0

when coming down initial velocity (u) = 0

gravitation force = 9.8

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