Question

A student made a cube shaped die from a card sheet. Instead of writing numbers 1,2,3,4,5,6 on its face, he wrote letters a,b,c,d,e,f one on each face randomly. if he rolls the die twice, find the probability that he gets a vowel on tne upper face both times​

Answer 1

Answer:

Step-by-step explanation: S={aa,ab,ac,ad,ae,af,ba,bb,bc,bd,be,bf,ca,cb,cc,cd,ce, cf, da,db,dc, dd,de,df, ea,eb,ec,ed,ee,ed,fa,fb,fc,fd,fe,ff }

Therefore, n( s ) = 36

A = { aa,ae,ea,we }

Therefore, n(A) = 4

Therefore, p(A)= n(A)/n(s)

= 4/36=1/9

Answer 2

Answer:S={aa,ab,ac,ad,ae,af,ba,bb,bc,bd,be,bf,ca,cb,cc,cd,ce, cf, da,db,dc, dd,de,df, ea,eb,ec,ed,ee,ed,fa,fb,fc,fd,fe,ff }

Therefore, n( s ) = 36

A = { aa,ae,ea,we }

Therefore, n(A) = 4

Therefore, p(A)= n(A)/n(s)

= 4/36=1/9

Read more on Brainly.in - https://brainly.in/question/13863233#readmore

Step-by-step explanation: