Question

a student measured the diameter of a small steel ball using a screw gauge of least count 0.001 cm the main scale reading is 5mm and zero of circular scale division coincide with 25 division above reference level if screw gauge have zero error of -0.004cm then correct diameter of ball

Answer 1

Hey dear,

● Answer -
Diameter = 0.529 cm

● Explanation -
# Given -
MSR = 0.5 cm
VSR = 25
LC = 0.001 cm
Zero error = -0.0004 cm

# Solution -
Diameter of steel ball measured by student -
Measured diameter = MSR + VSR × LC
Measured diameter = 0.5 + 25 × 0.001
Measured diameter = 0.525 cm

True diameter of steel ball must be -
True diameter = Measured diamter - Zero error
True diameter = 0.525 - (-0.004)
True diameter = 0.529 cm



Hope this helps you...