Question

A student measured the diameter of a small steel ball using a screw gauze of least count 0.001.the main scale reading is 5mm and zero of circular scale division concides with 25 division above the reference level.if screw gauze has a zero error of -0.004cm,the correct diameter of the ball is
(a). 0.521cm
(b). 0.525cm
(c). 0.529 cm
(d). 0.053 cm​

Answer 1

Answer:

C) 0.529cm

Explanation:

Diameter of the ball

= MSR + CSR × (least count) - zero error

= 5cm + 25 × 0.001 - (-0.004)

= 5 + 0.025 + 0.004

= 0.0529cm