Question

A student moves a box of books by pulling on a rope attached to a box. The student pulls with a force of 185N horizontally. The box has a mass of 35.0kg, and the coefficient of kinetic friction between the box and the floor is 0.27. Find the acceleration of the box.

Answer 1

Answer:

Given :- mass = 35 kg force = 185N The vertical component of 185 N = 185sin25 = 78.2N Weight = m * g = 35 * 9.8 = 343N therefore, Normal Reaction = 343 - 78.2 = 264.8 N frictional force =µ * N = 0.27 * 264.8 = 71.5 N Now, vertical component of 185 = 185cos25 = 167.7N therefore, net force acting = 167.7 - 71.5 = 96.2N now , f = ma then a = f/m or , a = 96.2 / 35 a = 2.75 m/s2 2) Vertical component of 185 = 185sin25 = 78.2N weight = mg = 35 * 9.8 = 343N component of mg along vertical =...

Explanation:

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Answer 2

Explanation:

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