A student of a class arranged a picnic. Each student contributed as many rupees as the number of students in the class. If the total contribution is ₹1156, find the strength of the class.
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let number of stidents be x.
Then money each student contributed is x
So total money= x multiplied by x.
x^2=1156. So we have to find the square root of 1156. If you know traditional method you shall arrive at x=34. Or go for trail and error.
For the square to be ending with 6 at units place, square root has to be ended with either 4 or 6. Now 1156 lies between 900 and 1600. So square root lies between 30 and 40. The possible values will be 34 and 36. Try with the former. 36*36=1156. This is very easy once you understand the trail and error method.
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Then money each student contributed is x
So total money= x multiplied by x.
x^2=1156. So we have to find the square root of 1156. If you know traditional method you shall arrive at x=34. Or go for trail and error.
For the square to be ending with 6 at units place, square root has to be ended with either 4 or 6. Now 1156 lies between 900 and 1600. So square root lies between 30 and 40. The possible values will be 34 and 36. Try with the former. 36*36=1156. This is very easy once you understand the trail and error method.
Mark this as brainliest.
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