Question

a student of mass 40 kg lift 5 kg bag from the ground to first floor of height 2m. work done by the boy​

Answer 1

Answer:

$work \: done = forse \: \times \: displacement \\ \: \: \: \: \: </p><p>force = mass \times acceleration \\ = 40kg \times ( - 9.8)m \: per \: {s}^{2 } \\ = - 392 \: newton \\ \\ work \: done = forse \: \times \: displacement \\ = - 392 \: newton \times 2m \: \\ = - 784 \: joule$