A student of mass 50 kg is standing on both feet. Estimate the pressure exerted by the student on the Earth. Assume reasonable value to any other quantity you need. Justify your assumption. You may use g= 10 m s2 By what factor will it change if the student lies on back?
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Thus the pressure exerted on the earth is 25 Pa.
Explanation:
We are given that:
- Mass of student = 50 Kg
- Gravitational acceleration "g" = 10 m/s^2
Solution:
According to newton's third law of motion.
F = ma
Force = m × a
F = (50 × 10) N = 500 N
Let the Area be 20 m².
We know that
Pressure = Force / Area
Pressure = (500 / 20)
Pressure "P" = 25 Pa
Thus the pressure exerted on the earth is 25 Pa.
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