A student of mass 50 kg is standing on both feet. Estimate the pressure exerted by the student on the Earth. Assume reasonable value to any other quantity you need. Justify your assumption. You may use g= 10 m s2 By what factor will it change if the student lies on back?
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Answer:
Mass (M) = 50 kg
Acceleration (A) = 10 m/s²
Force = M × A = (50 × 10) N = 500 N
Let the Area be 20 m².
Pressure = Force / Area = (500/20) Pa = 25 Pa
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