Question

A student of weight 400N takes 5sec to climb up an obstacle of height 2m.

Calculate the power consumed?​

Answer 1

Given,

Weight = 400 N

Time = 5 sec

Height = 2 m

To find,

The power consumed

Solution,

We can simply solve this numerical problem by using the following process.

Now,

Weight (mg) = 400 N

Time (t) = 5 sec

Height (h) = 2 m

Power (P) = ?

(Here, all of the physical quantities are SI units, so no unit conversion required.)

We know,

P.E. = m*g*h

where, P.E is potential energy, m is mass, g is acceleration due to gravity and h is the height gained.

Weight = m*g = 400 N

So, P.E. = 400 N * 2 m = 800 Joules.

Now,

Power consumed = (P.E/Time)

So,Power = (800 Joules/5 sec)

                = 160 Joules/sec

                = 160 Watt

So,The Power Consumed is  160 Watt.

Answer 2

Answer:

Power consumed is 160W

Explanation:

Given that,

Weight of Student(W)=400N

Height of obstacle(h)=2m

Time take to climb obstacle(t)=5sec

To find Power consumed we need to find work done.

Work Done=Force x Displacement

$W=F \times S$

Here F=Weight

S=Height

Therefore by substituting given values,we get

$W=400 \times 2 = 800J$

To find Power consumed,we use the following relation

$power = \frac{work}{time}$

By substituting given values

$power = \frac{800J}{5s} = 160W$

#SPJ2