A student performs a titration with different burettes and finds values of 25.2 mL, 25.25 mL and 25.0 mL. The number of significant figures in the average titre value is...?
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Answer:
We have 25.20,25.25 and 25.00 ml.
Average=
3
25.20+25.25+25.00
=
3
75.45
= 25.15=25.1
In case of division, the final answer will contain as many significant figures as there are in an number with least significant numbers.
So, the significant number is 3.
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