Question

A student performs the following experiment in order to calculate specific latent heat of fusion of ice. He takes a calorimeter of mass 5.0g containing 50g of water at 30°C. Into this calorimeter he adds 5g of dry ice at 0°C. When all the ice melts the final temperature recorded by him is 20C. (a) What is the total quantity of water in the calorimeter at 20°C? (b) What quantities of heat are released by water and calorimeter in attaining the temperature of 20°C? (c) What is the total amount of heat gained by the ice? (d) Calculate the value of latent heat of fusion of ice from the above calculations.

Answer 1

Answer:

4200J

Explanation:

Step 1: The energy required to change the state of 1 kg of a substance without affecting its temperature is known as the specific latent heat of that substance. There are two distinct latent temperatures for each substance: heat of fusion latent (the amount of energy needed to freeze or melt the substance at its melting point).

Step 2: A calorimeter is a tool used to measure heat, which is essential for calorimetry. It primarily consists of a metallic container constructed of materials that are effective electrical conductors, such as copper, aluminium, etc. The vessel's contents can also be stirred if necessary.

Step 3: Q_cal = mL

mL= 4200

L=4200/5=840 $Jg^{-1$

1) Total quantity of water at 20 degree C

= 5(ice)+55(water)

= 55g

2) M_w= 50g

T= 30 degree

$\begin{aligned}& M_{\hat{ice}} {}\left(0^{\circ} \mathrm{C}\right) \\& T_f=20^{\circ} \mathrm{C}\end{aligned}$

$\begin{aligned}Q(\text { cuaterl } & =50 \times 4.2 \times(30-10) \\& =50 \times 4.2 \times 20 \\& =1000 \times 4.2 \\& =4200 \mathrm{~J}\end{aligned}$

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