A student plucks two stretched metal strings A and E of different thicknesses. The A string vibrates at the rate of 40 vibrations per second and E string vibrates at a rate of 10 Vibrations per second. How many vibrations per second should be given to the string E in order to produce higher frequency sound than string A?
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3
Answer:
50
Explanation:
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4
The vibration per second should be assigned to the E unit to produce a higher-pitched sound than series A:
- The number of vibrations per second is known as frequency, measured in Hertz (1 Hz = 1 vibration per second).
- This vibration enters the outer ear and causes the eardrum to vibrate.
- We cannot hear the tremors being made by moving hands in the air because it is moving slowly.
- The reader snatches two stretched metal straps A and E with different thicknesses.
- A character unit A vibrates at a vibration rate of 40 per second = 40 / sec.
- The E-unit vibrates at a vibration rate of 10 per second = 10 / sec.
- High frequency sound = series A + series E
= 40 + 10 = 50 vibration / sec.
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