Science, asked by ayushdev10, 6 months ago

A student plucks two stretched metal strings A and E of different thicknesses. The A string vibrates at the rate of 40 vibrations per second and E string vibrates at a rate of 10 Vibrations per second. How many vibrations per second should be given to the string E in order to produce higher frequency sound than string A?​

Answers

Answered by akshatrauthan
3

Answer:

50

Explanation:

Answered by shilpa85475
4

The vibration per second should be assigned to the E unit to produce a higher-pitched sound than series A:

  • The number of vibrations per second is known as frequency, measured in Hertz (1 Hz = 1 vibration per second).
  • This vibration enters the outer ear and causes the eardrum to vibrate.
  • We cannot hear the tremors being made by moving hands in the air because it is moving slowly.
  • The reader snatches two stretched metal straps A and E with different thicknesses.
  • A character unit A vibrates at a vibration rate of 40 per second         = 40 / sec.
  • The E-unit  vibrates at a vibration rate of 10 per second = 10 / sec.
  • High frequency sound = series A + series E

                                       = 40 + 10 = 50 vibration / sec.

Similar questions