Question

A student prepared an aqueous solution of CuSO4 in beaker X and an aqueous solution of FeSO4 in beaker Y. He then dropped some iron pieces in beaker X and some zinc pieces in beaker Y. After about 10 hours he observed that the solutions in X and Y respectively appear:(A) blue and green(B) colourless and pale green(C) colourless and light blue(D) greenish and colourless

Answer 1

I think the answer should be (D) greenish and colourless 
as Fe displaces Cu from its salt solution in beaker X and forms FeSO4 that is green in colour as Fe is more reactive than Cu
and Zn displaces Fe from its solution in beaker Y and forms ZnSO4 that is colourless as Zn is more reactive than Fe
 

Answer 2

Answer: D

Explanation: since the blue color of copper sulphate

changes to green color because iron displaces copper from its salt solution...

Zinc displaces iron and changes to colorless