Question

A student pulls a box of books on a smooth horizontal floor with a force of 100N in a direction of 37o above the horizontal. If the mass of the box and the books is 40.0 kg, what is the acceleration of the box in m/s2?

Answer 1

Answer:

a = 1.99 m/s ^2

Explanation:

since there is no friction ,

net force will be equal to F.cos x,

F.cosx = ma { we get F.cosx by resolving it }

100 * cos 37° = 40 a

100 * 0.7986 = 40a

79.86 = 40a

a = 1.99 m/s^2

Answer 2

Given,

Force exerted by the student on the box = 100 N at an angle of 37°.

Mass of the box = 40 kg

To Find,

The acceleration of the box

Solution,

Let the acceleration of the box will be a.

since there is no friction,

The component of force in horizontal direction will be F.cos x

F.cosx = ma

100 * cos 37° = 40 a

100 * 0.7986 = 40a

79.86 = 40a

a = 1.99 m/s²

Hence, the aceeleration of the box will be 1.99 m/s².