A student reading a 426-page book finds that he reads faster as he gets into the
subject. He reads 19 pages on the first day, and his rate of reading then goes up by 3
pages each day. The number of days in which he will finish the book is
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Given, Sn = 426, a = 19 and d= 3
Given, Sn = 426, a = 19 and d= 3Sn= n/2 [ 2a + (n-1) d ]
Given, Sn = 426, a = 19 and d= 3Sn= n/2 [ 2a + (n-1) d ] 426 = n/2 [2 x 19 + (n-1) x 3 ]
Given, Sn = 426, a = 19 and d= 3Sn= n/2 [ 2a + (n-1) d ] 426 = n/2 [2 x 19 + (n-1) x 3 ] On solving, we get
Given, Sn = 426, a = 19 and d= 3Sn= n/2 [ 2a + (n-1) d ] 426 = n/2 [2 x 19 + (n-1) x 3 ] On solving, we get n=12 (for positive value of n)
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