A student recorded the mass of dry raisins as 6.0g and mass of raisins after soaking them in water for about four hours as 10.5g . Calculate the percentage of water absorbed by raisins.
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Mass of water =10.5-6=4.5
Now, take the percentage, as given below
(4.5/10.5)*100=42.85%
Now, take the percentage, as given below
(4.5/10.5)*100=42.85%
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Hey mate, here’s the answer. Pls match the answer and let never know if it’s incorrect. I hv a doubt between this answer and the answer above by another mate.
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