A student recorded the mass of dry raisins as20g and the mass of raisins after soaking as35g.calculate the precentage of water absorbed by the raisins? why did the raisins absorb water?
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Answer:
mass of dry raisins = 3g
mass of raisins after soaking = 4.8g
mass of water absorbed = 4.8 - 3 = 1.8 g
% of water absorbed = (1.8/3)*100 = 60%
Precaution:
Keep the raisins inside the water, not on surface
hope this helps you!
Answered by
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weight of raisins before soaking=20g
weight of raisins after soaking=35g
weight gained by raisins=35-20=15g
percentage of gain=15/20 x100
=3/4 x 100
=75 percent
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weight of raisins after soaking=35g
weight gained by raisins=35-20=15g
percentage of gain=15/20 x100
=3/4 x 100
=75 percent
hope this helps you
mark me as the brainiest
also follow me
also give this solution a 5 star and thanks
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