Question

A student recorded the mass of the dry raisins as 20 gram and the mass of raisin after soaking as 35 gram calculate the percentage of water by the raisin

Answer 1

Answer:

75%

Explanation:

dry raisins = 20 g

raisins after soaking = 35 g

so, water absorbed = 35-20 = 15

percentage of water by raisins =

$\frac{15}{20} \times 100$

= 75%