Question

A student releases a marble from the top of a 150cm ramp. The marble increases speed steadily and reaches the bottom of the ramp in 4.80s.

Answer 1

Answer:

Explanation:

Height of the ramp = h = 150cm or 1.5m

since the marble is released from a height, it is initially at rest and hence-

initial velocity = u = 0m/s

Now, since the speed of the marble is steadily increasing, the marble is moving with a constant acceleration = a

time taken to reach the bottom = 4.80s

From the equation - s = u*t + 1/2*a*t^2 = h = u*t + 1/2*a*t^2

Therefore - 1.5 = 0*t + 1/2*a*4.8*4.8

                   1.5 = 11.52a

                    a = 1.5/11.5 = 0.13

Hence, acceleration = 0.13m/s^2 or 13cm/s^2