Question

a student rides on a bicycle at 8 km hour and richest School 2.5 minute late the next day he increases speed to 10 km per hour reached School 5 minute only how far is the school from his house​

Answer 1

Let the distance be x km

Then, x8x8 - 2.5602.560 = x10x10 + 560560

x8x8 - x10x10 = 560560 + 2.5602.560

=> 2x802x80 = 7.5607.560

=> x = 7.5×802×607.5×802×60 = 5 km

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Answer 2

The distance is 5km.

Step-by-step explanation:

Consider the provided information.

Let the distance between school and his house is x km.

$Time=\frac{Distance}{Speed}$

A student rides on a bicycle at 8 km hour and richest School 2.5 minute late.

$\frac{x}{8}-\frac{2.5}{60}$

next day he increases speed to 10 km per hour reached School 5 minute early.

$\frac{x}{10}+\frac{5}{60}$

Equate both the equations.

$\frac{x}{8}-\frac{2.5}{60}=\frac{x}{10}+\frac{5}{60}$

$\frac{x}{8}-\frac{x}{10}=\frac{2.5}{60}+\frac{5}{60}$

$\frac{2x}{80}=\frac{7.5}{60}$

$x=\frac{80\times7.5}{60\times2}=5$

Hence, the distance is 5km.

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