A student running in a track meet started a run by reaching 200 m in 30 sec. She then ran 300 min in 30 sec. What is her acceleration?
Answers
Answer:
0.11 m/s
Formula: a = vf – vi / t
Solution:
200m in 30s – 200m/30s = 6.66 m/s – Initial Velocity (vi)
300m in 30s –300m/30s = 10 m/s – Final Velocity (vf)
30s + 30s = 60s
a = vf – vi / t
a = 10 m/s – 6.66 m/s / 60s
a = 3.34/60
a = 0.11 m/s2
Answer:
0.14 m/s²
Explanation:
The definition of acceleration is the rate of change of velocity per unit time. It is denoted by the letter a. that is, difference of the final and initial velocity divide by time taken.
Distance travelled is equal to 500 meters. Total time is equal to 60 seconds. We need to solve first the final velocity.Solving for final velocity:
Vf = 500 m / 60 s = 8.33 m/s
Given Data:
t ( time ) = 60 s
Vi ( initial velocity ) = 0 m/s (from start)
Vf ( final velocity ) = 8.33 m/s
a ( acceleration ) = ? unknown
We can use the formula (a = Vf - Vi / t) in order to solve for acceleration
a = Vf - Vi / t
= 8.33 m/s - 0 m/s / 60 s
= 8.33 m/s / 60 s
= 0.14 m/s²
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