Question

A student runs 2.5 km due West. After a rest, the student continue running 1.25 km due South. Determine the student’s displacement (resultant).​

Answer 1

Explanation:

west - 2.5 km

then south - 1.25 km

displacement - vectror sum of both () there are at 90.)

1.25)^2 +2.5^2 = displacement^2

displacement = 2.79 km