A student’s night camp was organized for class X students for two days and their accommodation was planned in tents. Each tent is in the shape of a cylinder surmounted by a conical top. If the height and diameter of the cylindrical part are 2. 1 m and 4 m respectively and the slant height of the top is 2.8 m. ( i) Find the area of the canvas used for making the tent . (ii) Also find the cost of the canvas of the tent at the rate of Rs 500 per m2. (Note that the base of the tent will not be covered with canvas).
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Given that,
Height (h) of the cylindrical part = 2.1 m
Diameter of the cylindrical part = 4 m
Radius of the cylindrical part = 2 m
Slant height (l) of conical part = 2.8 m
Area of canvas used = CSA of conical part + CSA of cylindrical part
Cost of 1 m2 canvas = Rs 500
Cost of 44 m2 canvas = 44 × 500 = 22000
Therefore, it will cost Rs 22000 for making such a tent.
Height (h) of the cylindrical part = 2.1 m
Diameter of the cylindrical part = 4 m
Radius of the cylindrical part = 2 m
Slant height (l) of conical part = 2.8 m
Area of canvas used = CSA of conical part + CSA of cylindrical part
Cost of 1 m2 canvas = Rs 500
Cost of 44 m2 canvas = 44 × 500 = 22000
Therefore, it will cost Rs 22000 for making such a tent.
AryaLi:
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