a student saves Rs 1 on first day Rs 2 on second day Rs 3 on third day and so onthen during mo month of April he has saved Rs
Anonymous:
465
Answers
Answered by
5
Answer:
Step-by-step explanation:
a=1
d=1
Since April has 30 days,
n=30
Sn=?
Sn=n÷2(2a+(n-1)d)
Sn=30÷2(2×1+(30-1)1)
Sn=15(2+29×1)
Sn=15×31
Sn=Rs 465.
HOPE THIS HELPS YOU
Answered by
2
Consider this in an Arithematic progression
1,2,3,4.............29,30
There has a proper equation to find the sum
But simple Here it is
add 1+30=31
and 2+29=31
.......
.......
15 pairs
so on....Dont be confused ,
Here how many 31 we get, 15 Right
To find the total 15 ×31
Which is 465
In My View
This student saves quite a good Amount of Money.
1,2,3,4.............29,30
There has a proper equation to find the sum
But simple Here it is
add 1+30=31
and 2+29=31
.......
.......
15 pairs
so on....Dont be confused ,
Here how many 31 we get, 15 Right
To find the total 15 ×31
Which is 465
In My View
This student saves quite a good Amount of Money.
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