Question

A student scored 18 marks out of 25
marks in the first test of Math. In the
second test he scored 22 marks in the
second test exceeds his first test by
INV 2009]
(1) 4%
(2) 8%
(3)/16%
(4) 80%​

Answer 1

Answer:

C IS THE ANSWER

Answer 2

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Given:

Total Test marks =25

Marks Scored in First test = 18

Marks Scored in Second test = 22

To find:

the percentage of marks in second test exceeds than in first test.

Solution

first we will find Total marks exceeded in second test.

Total marks exceeded in second test is the difference between Marks Scored in Second test and Marks Scored in First test.

framing the equation form we get;

Total marks exceeded in second test = 22 - 18 = 4

Now To find percentage of marks in second test exceeds than in first test we have to divide total marks exceeded in second test with Marks Scored in first test and then multiplied by 100.

framing in equation form we get;

percentage of marks in second test exceeds than in first test =

$\frac{4}{18} \times 100 \\ \\ = \: \: 22.22 \: \: \%$

Hence , there was 22.22% of marks exceeded in second test than first test.