Question

A student scored 24 marks in an examination and required 10 more marks to qualify. Another student obtained 36marks and got 2 marks more than the bare minimum to qualify. Find the maximum marks and the minimum percentage of marks required for qualifying.

Answer 1

HEY Buddy.......!! here is ur answer

Given that..... A student scored 24 percentage in an examination and required 10 more marks to qualify.

Then required marks to qualify = 24% + 10

And , an another student got 36% and got 2 more marks than bare minimum to qualify.

Then required marks to be qualified = 36%–2

According to the question.....

24% + 10 = 36% – 2

=> 12% = 12

Then, maximum Marks = 12×100/12

=> Maximum Marks = 100

And minimum percentage to be qualified = 24% + 10% = 34%

Therefore, the maximum marks = 100

and the minimum percentage = 34%

I hope it will be helpful for you.....!!

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Answer 2

Answer:

Let the maximum marks be x.

Then Pass mark for the 1st student =

100

20

×x+5

Pass mark for the 2nd student =

100

30

×x−20

Since pass marks are same for both the students

100

20x

+5=

100

30x

−20

⇒

100

10x

=25⇒x=250

∴ Pass mark =

100

20

×250+5=55

Pass percentage =

250

55

×100+5=22%

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