A student scores 25percent of the maximum marks and was declared failed by 44 marks, while another who secured half of the maximum marks, got 56 marks more then passing marks. The find passing percentage
Answers
Given:
Percentage of marks scored by student = 25% of maximum marks
To find:
The minimum percentage.
Solution:
Let us assume maximum marks as X.
Marks scored by the student = 25% of X
Since the student failed by 44 marks,
Therefore,
The minimum marks are = 25% of X + 44
= (25/100) X + 44
= (X/4) + 44 ( equation 1)
This shows,
If the student had scored (X/4) + 44 marks, he would have cleared the exam.
Another student scored half of the maximum marks,
Therefore, we can write,
Marks obtained by other student = (1/2) of X = (1/2)X = (X/2)
Since another student obtained 56 marks more than the minimum marks,
Therefore,
The minimum marks = (X/2) – 56 (Equation 2)
Equating equations 1 and 2,
(X/4) + 44 = ( X/2) – 56
(X/2) – ( X/4) = 44+ 56
X = 400
The maximum marks are 400 marks.
From equation 1,
The minimum marks = (400/4) + 44 = 144
144 marks out of 400 are required to clear the exam.
minimum percentage = (minimum marks / maximum marks) × 100
( 144/ 400 ) × 100
= 36
The minimum percentage is 36 marks.