Math, asked by udaydwivedi, 11 months ago

a student secure 32% marks in an examination and failed by 12 marks and other students secured 42% marks and got 28 marks more than the minimum required to pass from maximum marks and the pass percentage of marks

Answers

Answered by Anonymous
38
HEY DEAR ... ✌️

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Here's , Your Answer :-

Let total marks be x

32% of x + 12 = 42% of x - 28

42x/100 - 32x/100 = 40

10x/100 = 40

x/10 = 40

x = 400

400 is the maximum marks

Minimum passing marks =
=32/100 × 400 + 12
= 140

Pass percentage =
= 140/400 × 100
= 35%


Some Basic formulaes are :-

1.) Gain = S.P - C.P

2.) Loss = C.P - S.P

3.) Gain % = Gain x 100 C.P

4.) Loss % = Loss x 100. C.P

Extra information :-

Basically Profit and loss problems are used in accounts section for banking jobs or accountant jobs . CA and all simply for commercial works . And , also helpful in business .




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HOPE , IT HELPS ... ✌️
Answered by tiwariparthkumar
5

Answer:

400 is the maximum marks and 35% was the pass %

Step-by-step explanation:

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