A student secures 38% of the total marks in an
exam and gets 18 marks more than the pass mark.
A second student secures 27% of the total marks in
the same exam and fails by 37 marks. What is the
pass mark as a percentage of the total marks?
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Let x=Total marks
Let y=Passing marks
38% of Total marks=Passing marks+18 (given)
(38/100)*x=y+18………(1)
27% of Total marks=y-37 (given)
(27/100)*x=y-37……….(2)
From equation 1&2
0.38x=y+18
0.27x=y-37
Solving.
X=500 & Y=172
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