Question

A student secures 90%,60% and 54% marks in three test papers with maximum marks 100, 150 and 200 respectively. Find his aggregate percentage​

Answer 1

Answer:

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Answer 2

Step-by-step explanation:

Marks obtained in 1st test paper=

90% of 100

= 90/100×100

= 90

Marks obtained in 2nd test paper=

60% of 150

= 60/100×150

= 90

Marks obtained in 3rd test paper=

54% of 200

= 54/100×200

= 108

So, total marks obtained in three test papers=

(90+90+108)

= 288

Total maximum marks in three test papers =

(100+150+200)

= 450

So,his aggregate percentage=

{(total marks obtained in three test papers)/(Total maximum marks in three test papers)×100}%

= (288/450×100)%

= 64%

Hence, his aggregate percentage is 64%.

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