Question

A student solved 6 out of 10 problems correctly what is the ratio of the correct problems to the incorrect problems?

Answer 1

Given:

A student solved 6 out of 10 problems correctly.

To find:

The ratio of the correct problems to the incorrect problems.

Solution:

As given,

The total number of problems = 10.

Out of 10, the number of the problems solved by the student correctly = 6

Thus, the number of problems solved by the student incorrectly = total number of problems - problems solved correctly = 10 - 6 = 4.

So,

$\frac{number \: of \: correct \: problems}{number \: of \: incorrect \: problems} = \frac{6}{4}$

On solving the above ratio, we get

$\frac{number \: of \: correct \: problems}{number \: of \: incorrect \: problems} = \frac{3}{2}$

Hence, the ratio of the correct problems to the incorrect problems is 3:2.

Answer 2

Answer:

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Step-by-step explanation:

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