Question

) A student takes a green leaf from the plant and boils it in a alcohol bath for removal of chlorophyll. After this treatment, the student adds a few drops of iodine to the boiled leaf using syringe dropper. After some time, the student observes that the leaf turns blue-black in colour. What can be evaluated from this?​

Answer 1

Answer:

The iodine reacts with the starch present in the leaf

that indicates the occurrence of

photosynthesis.

Explanation:

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Answer 2

Answer:

Iodine reacts with the starch present in the leaf, thereby indicating the event of photosynthesis.

Explanation:

• Plants produce their own food through the process of photosynthesis.
• Chlorophyll is an essential photosynthetic pigment as it absorbs the required energy from sunlight.
• The glucose produced as an end product of photosynthesis is utilized in many ways.
• It is used for respiration and ATP generation, it is used in the formation of cellulose and it is also stored in the various parts of the plant in the form of starch.

• When iodine is added to the boiled leaves it reacts with the starch present in the leaf and turns blue/black in color, indicating that the process of photosynthesis has taken place. Thereby, signifying the importance of chlorophyll.

• Whereas, before the experiment is conducted, if the plants are kept in a dark room for 24 hours and the same test is repeated. The results will be different.
• The iodine will turn reddish-brown in color since no starch is present in the leaf as the process of photosynthesis did not take place in the dark room.

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