A student throws a coin vertically downward from the top of a building. The coin leaves the thrower's hand with a speed of 150 m/s. How far does it fall in 2.00?
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from second equation of motion,
S = u.t + 1/2 a.t^2
S = 150 × 2 + 1/2 ×10×4
S = 300 + 20
S = 320 m
S = u.t + 1/2 a.t^2
S = 150 × 2 + 1/2 ×10×4
S = 300 + 20
S = 320 m
Answered by
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In this question we will apply Newton’s second equation of motion to find the answer.
s = ut + ½ (at2)
u = 150 m / s
t = 2 s
a = g = 9.8 m/s
s = 150 * 2 + 1/2 * ( 9.8 * 4 )
s = 300 + 19.6
s = 319.6 m
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